Question

pls solve the q in the file

Answer 1

Answer:

$\left \{ {{p=3} \atop {q=1}} \right.$

Step-by-step explanation:

First, we'll expand $(x-p)^2+q$. It's equal to $x^2-2px+p^2+q$.

Then, we'll compare this to $x^2-6x+10$.

• The terms $x^2$ are the same
• The terms with $x$ are $-2px$ and $-6x$ in the two expressions respectively, so they must be equal. We have $-2px=-6x$, so p=3.
• The remaining terms are $(p^2+q)$ and $10$. They must be equal. We have $p^2+q=10$. Substituting in $p=3$, we get $9+q=10$, so q=1.

Answer 2

Answer:

p = 3, q = 1

Step-by-step explanation:

Using the method of completing the square

add/ subtract ( half the coefficient of the x- term )² to x² - 6x

x² + 2(- 3)x + 9 - 9 + 10

= (x - 3)² + 1 ← in the form (x - p)² + q

with p = 3 and q = 1