Question

How to find the total resistance, current going through, and the total energy used

Answer 1

Answer:

Explanation:

a) Re = 2 + (1/(1/3 + 1/1)) + 4 = 6¾ Ω

b) Current supplied by battery = 18 / 6¾ = 2⅔ A

   Voltage across the 3 Ω resistor = 18 - 2⅔(2 + 4) = 2V

   I₃ = 2 V /3 Ω = ⅔A

c) A Watt is 1 J/s

   E = 18 V(2⅔ A)(2 hr)(3600 s/hr) = 345,600 J