Answer:
Explanation:
The maximum force the car can generate is
F = ma = 1150(5.50) = 6325 N
When this force is used to move two cars
a = F/m = 6325 / (1150 + 1450) = 2.43269... = 2.43 m/s²
a) m₁g = m₂gsinθ
m₁ = m₂sinθ
m₁ = 25.0sin29.0 = 12.1202...
m₁ = 12.1 kg
b) F = ma
m₁g - m₂gsinθ = (m₁ + m₂)a
a = g(m₁ - m₂sinθ) / (m₁ + m₂)
a = 9.81(5.00 - 25.0sin29.0) / (5.00 + 25.0) = -2.32831...
a = - 2.33 m/s²
c) Provided the initial velocity is zero
d = ½at²
d = ½(2.33)2.00²
d = 4.66 m
