A Canadian nickel (five-cent coin) contains
8.13 X 1020 atoms of nickel, Ni(s), along with other
metals. What amount (in mol) of nickel is in a
Canadian nickel?

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Answer:

1.34x10^-3 moles.

Explanation:

To convert from atoms to moles, you'd need to multiply the value of atoms by a number called the Avogadro's Constant, used in converting moles 6.023x10^23, to get the moles.

8.13x10^20 divided by 6.023x10^23=0.0013498

Since the significant figures tell us to use three digits (in case of multiplication or division, use the smallest number of sig figs involved), so we should do 1.34x10^-3 moles.

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