EXPLANATION:
Given AP is 4,9,14,...,254
First term = 4
Common difference =9-4 = 5
Let nth term = 254
We know that
nth term of an AP = an = a+(n-1)d
Now,
an = 254
⇛4+(n-1)(5) = 254
⇛4+5n-5 = 254
⇛5n-1 = 254
⇛5n = 254+1
⇛5n = 255
⇛n = 255/5
⇛n = 51
254 is the 51st term of the AP
Now 10th term from the end = 51-10+1 = 42
42th term = a+41d
⇛4+(41)(5)
⇛4+205
⇛209
Answer: The 10th term form the end of the given AP is 209.
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