Respuesta :
Answer:
1st term: -3
2nd term: 6
3rd term: 21
4th term: 42
Step-by-step explanation:
This problem is unclear if I need to find the first 4 terms or the 4th term. I'm going to assume both possibilities.
To find the value of a term n, you'd just have to plug in that value n into the equation. When finding the first four terms of a sequence, you have to plug in the numbers 1, 2, 3, 4. When you plug in those numbers, you get those said answers.
1st term: 3(1^2)-6=-3
2nd term: 3(2^2)-6=6
3rd term: 3(3^2)-6=21
4th term: 3(4^2)-6=42
When assessing this problem, it is a geometric sequence with a common multiplier.
EXPLANATION:
Given that an = 3n²-6
Put n = 1 then
a1 = 3(1)²-6
⇛a1 = 3(1)-6
⇛a1 = 3-6
⇛a1 = -3
Put n=2 then
a2 = 3(2)²-6
⇛a2 = 3(4)-6
⇛a2 = 12-6
⇛a2 = 6
Put n = 3 then
a3=3(3)²-6
⇛a3 = 3(9)-6
⇛a3 = 27-6
⇛a3 = 21
Put n=4 then
a4 = 3(4)²-6
⇛a4 = 3(16)-6
⇛a4 = 48-6
⇛a4 = 42
Answer: The four terms of the sequence are -3,6,21,42
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