Answer:
x = 3
y = 1
Step-by-step explanation:
1. First step is to identify which strategy you will use to solve this system of equations: I will use Elimination to solve this system of equation:
2. We need to that can isolate x or y, I have identified and we can multiply the top by -4 and bottom equation by 3.
We get:
[tex]\left \{ {{-3x+8y=-1} \atop {-4x+7y=-5}} \right.[/tex]
Let’s add our factors in and eliminat the x’s:
[tex]\left \{ {{-4(-3x+8y=-1)} \atop {3(-4x+7y=-5)}} \right.[/tex]
Now let’s factor the numbers through the equation and add the equations together:
[tex]\left \{ {{12x-32y=4} \atop {-12x+21y=-15}} \right.[/tex]
Let’s add:
…and we get
[tex]-11y=-11[/tex]
[tex]y = 1[/tex]
We know that y = 1 so we can subsitute and figure out x:
[tex]-3x+8=-1[/tex]
As you can see I have taken the firsth equation and substituted y = 1: Let’s find x:
[tex]-3x=-9[/tex]
[tex]x = 3[/tex]
x = 3 and y = 1
