Question

a 5-kg block being pulled across a table by a horizontal force of 78 n also experiences a frictional force of 12 n. what is the acceleration of the block? the acceleration of the block is

Answer 1

The net force on the block acting parallel to the surface is

∑ F = 78 N - 12 N = (5 kg) a

Solve for the acceleration a :

66 N = (5 kg) a

a = (66 N) / (5 kg) = 13.2 m/s²