Question

another club has 20 members. 12 boys and 8 girls. two of the members are chosen at random. what is the probability that a girl and boy are chosen

Answer 1

Answer:

$\frac{6}{25}$

Step-by-step explanation:

P(girl)

= 8/20

= 2/5

P(boy)

= 12/20

= 3/5

So P(girl and boy)

= $\frac{2}{5}*\frac{3}{5}$

= $\frac{6}{25}$