Respuesta :
Answer:
- See below
Step-by-step explanation:
Part 1
1. Given line:
y = -3/2x + 6
Parallel line has same slope of -3/2 and passes through the point (2, -1).
Find its y-intercept:
- - 1 = -3/2*2 + b
- -1 = - 3 + b
- b = 2
The line is:
- y = -3/2x + 2
Correct choice is C
2.
The line is:
- x = -3
It has undefined slope and is parallel to the y-axis.
The line parallel to this and passing through the point (4, 2) is:
- x = 4
Correct choice is D
3.
The line given:
- y = 1/2x - 1
Parallel line has same slope of 1/2 and passes through the point (-2, 3).
Find its y-intercept:
- 3 = 1/2(-2) + b
- 3 = - 1 + b
- b = 4
The line is:
- y = -1/2x + 4
Non of the answer choices match this, something is wrong with given
4.
Given line:
y + 1 = 2(x - 3),
Converting this to slope-intercept:
y = 2x - 6 - 1
y = 2x - 7
The line parallel to this has the slope of 2 and passes through the point (5, 0)
Its y-intercept is:
- 0 = 2*5 + b
- b = - 10
The line is:
- y = 2x - 10
Non of the answer choices match this, something is wrong with given
Part 2
Compare the slopes of the lines. They are parallel if slopes are same, perpendicular if the product of the slopes is -1.
1.
The slopes are 1 and - 1, so their product is - 1.
- The lines are perpendicular
2.
Rewrite the second line as:
- 2x + y = 7 ⇒ y = -2x + 7
The slopes are same, - 2.
- The lines are parallel.
3.
Rewrite the second line as:
- - x + 4y = 0 ⇒ 4y = x ⇒ y = 1/4x
The slopes are 4 and 1/4.
- The lines are neither parallel nor perpendicular.
Part 3
1.
Parallel lines have same slopes, they can be negative too.
- It can sometimes be true, when positive slopes are same.
2.
Perpendicular lines can't have same slopes.
- It is never true.
Answer:
PT:1
1. (2,-1) ;
y = -3/2x + 6.....[1]
now
comparing above equation with y=mx+c we get,
m=-3/2
since another line is parallel ;
slope of another line is m=M=-3/2
since it passes through (2,-1)
now
equation of line is;
y-y1=m(x-x1)
y-(-1)=-3/2 (x-2)
y+1=-3/2x+3
y=-3/2 x+3-1
c. y=-3/2 x +2 is a required equation.
2. (4,2) ;
x = -3
it means parallel to y-axis
m=y/x
slope of another line is same so,slope is 0/-3=0
since it passes through (4,2)
now
equation of line is;
y-y1=m(x-x1)
y-2=0 (x-4)
a. y=2 is a required equation.
3. (-2,3) ;
y = 1/2x - 1
comparing above equation with y=mx+c we get,
m=1/2
since another line is parallel ;
slope of another line is m=M=1/2
since it passes through (-2,3)
now
equation of line is;
y-y1=m(x-x1)
y-3=1/2 (x-(-2))
y-3=1/2 x+1
y=1/2 x +1+3
a. y=1/2x +4 is a required equation.[not sure]
4. (5,0) ;
y + 1 = 2(x-3)
y+1=2x-6
y=2x-6+1
y=2x-5
comparing above equation with y=mx+c we get,
m=2
since another line is parallel ;
slope of another line is m=M=2
since it passes through (5,0)
now
equation of line is;
y-y1=m(x-x1)
y-0=2 (x-5)
b. y=2(x-5) is a required equation.[not sure]
Step-by-step explanation: