Hey There!
Please explain me the maths problem given in the attachment....
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Don't answer if you don't know
Need answer with explanation
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Hey TherePlease explain me the maths problem given in the attachmentNote Dont spam and dont copy Dont answer if you dont know Need answer with explanation Im no class=

Respuesta :

[tex]\large\underline{\text{Meaning of the expression}}[/tex]

Here is the explanation for each symbol.

[tex]\displaystyle\blue{\bullet}\ \sum^{n}_{k=1}\dfrac{1}{k}[/tex] is the area of the rectangles.

[tex]\displaystyle\blue{\bullet}\ \ln n[/tex] is the area bounded by [tex]y=\dfrac{1}{x}[/tex], [tex]x=1[/tex], [tex]x=n[/tex] and the x-axis.

[tex]\displaystyle\blue{\bullet}\ \lim_{x\to\infty}[/tex] is the approaching value of an expression, as calculation repeats more and more times.

In the attachment, three areas are bounded by different colors.

[tex]\displaystyle\blue{\bullet}\ \text{Grey region: The area that the domain of }\ln n\text{ cannot cover.}[/tex]

[tex]\displaystyle\blue{\bullet}\ \text{Red region: The area under }y=\dfrac{1}{x}\text{.}[/tex]

[tex]\displaystyle\blue{\bullet}\ \text{Purple region: The difference between the curve and rectangle.}[/tex]

[tex]\large\underline{\text{Note}}[/tex]

The number, [tex]\displaystyle\gamma=\lim_{x\to\infty}\bigg(\sum^{n}_{k=1}\dfrac{1}{k}-\ln n\bigg)[/tex] is Euler-Mascheroni constant.

[tex]\large\underline{\text{Rational or irrational?}}[/tex]

It is not found whether the value is rational or irrational. By continued fraction method, it is proved that the denominator must be greater than [tex]10^{244663}[/tex] by Papanikolaou in 1997.

[tex]\large\underline{\text{Graphical property}}[/tex]

The number has the following property about the area.

[tex]\blue{\bullet}\ \gamma=\text{(Area under the curve }\dfrac{1}{x})-\text{(Harmonic series)}[/tex]

This property is used in the approximation of the harmonic series, as [tex]\gamma[/tex] is around 0.577. And it is since the area of the purple region gets less and less. We get the following approximation.

[tex]\blue{\bullet}\ \ln n-\gamma\approx\text{(Harmonic series)}[/tex]

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