Question

how many grams of no are required to produce 145 g of n2 in the following reaction? 4nh3(g) 6no(g) → 5n2(g) 6h2o(l)

Answer 1

Answer:

186.357 grams

Explanation:

Convert grams of $N_{2}$ to moles:

145g $N_{2}$  x ( 1 mole $N_{2}$  ÷  28.02 g $N_{2}$ ) = 5.174 moles $N_{2}$

multiply the mole ration of NO by $N_{2}$ :

5.174 moles $N_{2}$  x  ( 6 moles NO ÷ 5 moles $N_{2}$ ) = 6.209 moles NO

now convert moles to grams:

6.209 moles NO x ( 30.01g NO ÷ 1 mole NO) = 186.357 grams NO

molar mass of $N_{2}$ is 28.02g/mole

molar mass of NO is 30.01g/mole