Question

Raphael graphed the functions g(x)=x 2 and f(x)=xâÂ’1. How many units below the y-intercept of g(x) is the y-intercept of f(x)? A coordinate plane with 2 lines drawn. The first line is labeled f(x) and passes through the points (0, negative 1) and (1, 0). The second line is labeled g(x) and passes through the points (negative 2, 0) and (0, 2). âÂ’3 units âÂ’1 units 2 units 3 units.

Answer 1

The y-intercept of g(x) is -3 units below the y-intercept of f(x).

Given to us,

equation 1, g(x) = x + 2

equation 2, f(x) = x - 1

co-ordinates of lines,

Also, it is given that the co-ordinates of lines,

the first line is f(x), passes through the points (0, -1) and (1, 0);

the second line is g(x), passes through the points (-2, 0) and (0, 2).

The picture below can be seen for reference.

The lines are parallel to each other, where g(x) is the red line, whereas f(x) is the blue line. thus, will have a constant space between them.

Therefore, for the y-intercept, the distance between any two points will be constant which is 3 units.

Hence, the y-intercept of g(x) is -3 units below the y-intercept of f(x).

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