Question

Lorne subtracted 6x3 â€"" 2x 3 from â€""3x3 5x2 4x â€"" 7. Use the drop-down menus to identify the steps Lorne used to find the difference. 1. (â€""3x3 5x2 4x â€"" 7) (â€""6x3 2x â€"" 3) 2. (â€""3x3) 5x2 4x (â€""7) (â€""6x3) 2x (â€""3) 3. [(â€""3x3) (â€""6x3)] [4x 2x] [(â€""7) (â€""3)] [5x2] 4. â€""9x3 6x (â€""10) 5x2 5. â€""9x3 5x2 6x â€"" 10.

Answer 1

After subtraction Lorne will get $\bold{-9x^3+5x^2+6x-10}$.

Given equation:

1.)   $6x^3-2x+3$

2.)   $-3x^3+5x^2+4x-7$

Subtracting the equation 1 from equation 2, thus,

$-3x^3+5x^2+4x-7 -(6x^3-2x+3)$

Now, according to BODMAS we will solve brackets first, therefore, after removing the bracket negative will become positive and vice versa.

$-3x^3+5x^2+4x-7 -(6x^3-2x+3)\\=-3x^3+5x^2+4x-7 -6x^3+2x-3$

After rearranging,

$=-3x^3+5x^2+4x-7 -6x^3+2x-3\\=-3x^3 -6x^3+5x^2+4x+2x-7-3$

Solving further, we get,

$=-3x^3 -6x^3+5x^2+4x+2x-7-3\\=-9x^3+5x^2+6x-10$

Hence, after subtraction Lorne will get $\bold{-9x^3+5x^2+6x-10}$.

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