Question

what is the average kinetic energy of a molecule of oxygen at a temperature of 300. k?

Answer 1

Answer:

Explanation:

The average kinetic energy of the molecules is 5.66 × 10⁻²¹ J.

Answer 2

Step 1

The average translational kinetic energy of the molecule is influenced by its average temperature, hence it is correlated to the temperature ∈

   $\epsilon_{avg} =\frac{3}{2} K_{B} T$    take it as equation 1

where $K_{B}$ is Boltzmann's constant and SI unit is

        $k_{\text{B}} = 1.38 \times 10^{-23} \mathrm{~J/K}$

       $T= 300K$

Step 2

substitute the values of $K_{B}$ and T in equation 1 to get $\epsilon_{avg}$

     $\epsilon_{avg} =\frac{3}{2} K_{B}T$

             $= \frac{3}{2} (1.38\times10^{-23} \mathrm{~J/K}) ( 300 \mathrm{~K})$

             $={6.21 \times 10^{-21} \mathrm{~J}} \end{align*}$

The average kinetic energy of a oxygen molecule is  $\epsilon_{avg} =6.21 \times 10^{-21} \mathrm{~J}$

learn more about average kinetic energy of a molecule here https://brainly.com/question/9078768

#SPJ2