Answer:
2.24 grams of CO2, assuming the reaction involves LiOH reacting with CO2.
Explanation:
0 grams, if you have a bottle of LiCO3 on the shelf.
Or should we assume we are reacting CO2 with a lithium compound?
We need to start with a balanced equation. That is why I added the perceptive, (but crass), remark of "get it from the shelf."
Here is one reaction that could be useful involving lithium hydroxide:
2LiOH + CO2 = Li2CO3 + H2O
This tells us that 1 mole of CO2 will produce 1 mole of Li2CO3. Lithium carbonate has a molar mass of 73.9 grams/mole. If we want 3.75 grams of the grimy stuff, we'll need (3.75g/73.9 g/mole) or 0.0508 moles of Li2CO3.
We'll need the same number of moles of CO2 to produce the Li2CO3, 0.0508 moles of CO2.
The molar mass of CO2 is 44 grams/mole. 0.0508 moles of CO2 is (0.0508 moles)*(44 grams/mole) = 2.24 grams of CO2.
If the reaction is different from the one I assumed here, do the same calculations using that balanced equation.
