Question

how would you expect the solubility of barium sulfate in pure water to compare to its solubility in 0.10 m nacl

Answer 1

Answer:

barium sulfate is insoluble (unable to dissolve) in water.

the general equation for the reaction between solid barium sulfate and nacl solution is this:

BaSO4 (s) + 2NaCl (aq) --> BaCl (aq) + Na2SO4 (aq)

to sum this up, to compare the solubility,

1. barium sulfate cant dissolve in pure water.

2. barium sulfate dissolves in nacl solution to give aqueous (aq) barium chloride (bacl) and aqueous sodium sulfate (na2so4), as shown in the equation above.

good luck!

Answer 2

The solubility of barium sulfate in pure water to zero as compare to the solubility in NaCl solution.

What is solubility?

Solubility is a property of any substance that defines how easily can be any substance will get dissolved or show dissolution.

• Barium sulphate is insoluble in water beacuse it has higher lattice energy as well as higher size of cations & anions as compare to water, due to which water is not able to attract these ions towards itself affectively.

• Barium sulphate is soluble in the NaCl solution as this solution having ions which have more power to attract the ions of barium sulphate and show dissolution. Chemical reaction for this will be represented as:

         BaSO₄ (s) + 2NaCl (aq) → BaCl (aq) + Na₂SO₄ (aq)

Hence, barium sulphate is insoluble in water.

To know more about solubility, visit the below link:
https://brainly.com/question/16903071