Answer:
Vertical asymptote is at [tex]x=-3[/tex]
Step-by-step explanation:
Let us plot the function
Here
[tex]\frac{x-5}{x^{2}-2x-15}=\frac{x-5}{(x-5)(x+3)}\\\\=\frac{1}{x+3}[/tex]
Function does not exits at [tex]x=-3[/tex]
Vertical asymptote is at [tex]x=-3[/tex]