Question

Which quantity of fruit contains an amount of vitamin C closest to the combined


amount of vitamin C in 50 g grams of acerola cherries and 150 g grams of


kiwifruit?


A. 2,000 g grams of black currants


B. 800 g grams of guava


C. 1,800 g grams of pineapple


D. 600 g grams of strawberries

Answer 1

Answer:

c would be the closest due to the total amount of vitamin c in the objects.

Answer 2

The quantity of fruit which contains an amount of vitamin C closest to the combined content is: C. 1,800 g grams of pineapple.

How to calculate the amount of vitamin.

In this exercise, we would determine the amount of vitamin C that is present in a combination of 50 grams of acerola cherries and 150 grams of kiwifruit.

For acerola cherries:

100 grams of acerola cherries = 1678 mg.

50 grams of acerola cherries = X mg.

Cross-mutiplying, we have:

X = 83,900/100 = 839 mg.

For kiwifruit:

100 grams of kiwifruit = 105 mg.

150 grams of kiwifruit = Y mg.

Cross-mutiplying, we have:

Y = 15,750/100 = 157.5 mg.

Combine vitamins = 157.5 + 839 = 996.5 mg.

Based on intuition, we would choose 1,800 grams of pineapple.

100 grams of pineapple = 56 mg

1,800 grams of pineapple = Z mg.

Cross-mutiplying, we have:

Z = 100,800/100 = 1008 mg.

Thus, 996.5 mg of vitamin C is closest to 1008 mg.

Note: If you do the above computations for other quantities of fruit, you'll get a value far from 996.5 mg.

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