please help me asap
ty :)

Answer:
y = 5x+7
Step-by-step explanation:
Parallel lines have the same slope so y = 5x+9 is in slope intercept form
y = mx+b where m is the slope and b is the y intercept
The slope is 5
The new line will have a slope of 5
y = 5x+b
We know a point on the line (-2,-3)
Substitute this point into the equation
-3 = 5(-2)+b
-3 = -10+b
-3+10 = b
7 = b
y = 5x+7
[tex]\huge{\purple{\underline{\underline{\bf{\pink{ANSWER:-}}}}}}[/tex]
The line parallel to y = 5x + 9 is given in the form of y = mx + c. Here,
The new line will have a y-intercept and a slope of line which is given by y = 5x + b. The point on line is (-2, -3).
Placing this point in the upper equation,
[tex]:\implies\rm{ - 3 = 5( - 2) + b}[/tex]
[tex]:\implies\rm{ - 3 = - 10 + b}[/tex]
[tex]:\implies\rm{ - 3 + 10 = b}[/tex]
[tex]:\implies\rm{7 = b}[/tex]
Placing b = 7 in equation we get,
[tex]:\implies\rm{y = 5x + b}[/tex]
[tex]:\implies\rm{y = 5x + 7}[/tex]