Question

The function D(t) defines a traveler’s distance from home, in miles, as a function of time, in hours. D(t) = StartLayout enlarged left-brace 1st Row 1st column 300 t 125 , 2nd column 0 less-than-or-equal-to t less-than 2. 5 2nd Row 1st column 880, 2nd column 2. 5 less-than-or-equal-to t less-than-or-equal-to 3. 5 3rd Row 1st column 75 t 612. 5, 2nd column 3. 5 less-than t less-than-or-equal-to 6 EndLayout Which times and distances are represented by the function? Select three options. The starting distance, at 0 hours, is 300 miles. At 2 hours, the traveler is 725 miles from home. At 2. 5 hours, the traveler is 875 miles from home. At 3 hours, the distance is constant, at 880 miles. The total distance from home after 6 hours is 1,062. 5 miles.

Answer 1

The distance in given time t is determined by substituting the value of time and solving the equation.

At 2 hours, the traveler is 725 miles from home.

At 3 hours, the distance is constant, at 880 miles.

The total distance from home after 6 hours is 1,062.5 miles.

Given that,

The function D(t) defines a traveler’s distance from home, in miles, as a function of time, in hours.

D(t) = 300t + 125

We have to determine,

Which times and distances are represented by the function?

According to the question,

The function D(t) defines a traveler’s distance from home, in miles, as a function of time, in hours.

D(t) = 300t + 125

1. The starting distance at 0 hours is ;

At $0 \leq t < 2.5$

Then,

$\rm D(t) = 300t + 125 ;\\\\\ D(0) = 300(0) + 125 = 125 \ miles$

The starting distance, at 0 hours, is 125 miles.

2. The distance at 2 hours is,

$\rm D(t) = 300t + 125 ;\\\\\ D(2) = 300(2) + 125\\\\ D(2) =600+125\\\\ D(2) = 725 \ miles$

At 2 hours, the traveler is 725 miles from home.

3. The distance at t = 2.5 hours is,

At 2.5 ≤ t ≤ 3.5

D(2.5) = 880 miles (Fixed)

At 2.5 hours, the traveler is 880 miles from home.

4. The distance at t = 3 hours is,

2.5 ≤ t ≤ 2.5

D(3) = 880 miles

At 3 hours, the distance is constant, at 880 miles.

5. The distance at t = 6 hours is,

3.5 < t ≤ 6

$\rm D(t) = 300t + 125 ;\\\\\ D (6)= 75(6) + 612.5\\\\ D(6) = 450 + 612.5\\\\D(6) = 1062.5 miles$

The total distance from home after 6 hours is 1,062.5 miles.

For more details about Average distance refer to the link given below.

https://brainly.com/question/25969947