Using the solubility product of the saturated solution, the mass of BaF2 dissolved is 0.083 g.
The equation of the reaction is obtained from;
BaF2(s) ⇄ Ba^+(aq) + F^-(aq)
The concentration of the substance can be obtained from the Ksp as follows;
Ksp = [Ba^2+] [2F^-]^2
Ksp = 4x^3
x = ∛Ksp/4
x = ∛ 1.00 x 10-6/4
x = 6.3 x 10^-3 M
Given that;
mass/molar mass = concentration x volume
molar mass = 175 g/mol
concentration = 6.3 x 10^-3 M
volume = 75.0 ml or 0.075 L
Mass = ?
Mass = concentration x volume x molar mass
Mass = 6.3 x 10^-3 M x 0.075 L x 175 g/mol
Mass = 0.083 g
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