Answer:
First term of the sequence is [tex]11[/tex]
Step-by-step explanation:
Let [tex]a[/tex] be the first term and [tex]d[/tex] be the common difference
We have
The sum of the second term and the ninth term of an arithmetic sequence is [tex]-5[/tex]
[tex]a+(2-1)d+a+(9-1)d=-5\\\\2a+9d=-5---eqn1[/tex]
The sum of the third and fourth terms of the same sequence is [tex]7[/tex]
[tex]a+(3-1)d+a+(4-1)d=7\\\\2a+5d=7---eqn2[/tex]
eqn 1 - eq2
[tex]4d=-12\\\\d=-3[/tex]
Substituting in eqn 1
[tex]2a+9\times -3=-5\\\\2a=22\\\\a=11[/tex]
First term of the sequence is [tex]11[/tex]