Question

Solve the system of equations.
\begin{aligned} & -4x+3y = -2 \\\\ & y=x-1 \end{aligned}
​

−4x+3y=−2
y=x−1
​

Answer 1

Answer:

x = -1 ; y=0

Step-by-step explanation:

We plug in the y, from the second equation, in the first one. By doing so we obtain:

-4x +3(x-1) = -2

-4x + 3x - 3 =-2

-x = 1

x= -1

Now we take this value and plug it in the second equation:

y = 1-1 = 0

Solution:

(-1,0)

Answer 2

-4x+3(x-1)=-2
-4x+3x-3=-2
-4x+3x=-2+3
-x=1
x=-1

y=-1-1
y=-2

(x,y)
(-1, -2)