Question

Answer the following.
1 Bharat borrows a certain sum of money at
5% pa. If he pays 2000 as simple interest
at the end of the first year, find the sum he
borrowed

Answer 1

Answer:

40000

Step-by-step explanation:

Simple interest (I) is calculated as

I = $\frac{PRT}{100}$

P is the amount borrowed , R is the interest and T the time in years

Here I = 2000 , R = 5 and T = 1 with P to be found , then

2000 = $\frac{P(5)(1)}{100}$ ( multiply both sides by 100 )

5P = 200000 ( divide both sides by 5 )

P = 40000

Answer 2

Answer:

The sum (Principal) is Rs.4000.

Step-by-step explanation:

Given :

• Simple interest = Rs.2000
• Time = 5% per annum
• Time = 1 year

To Find :

• Principle

Using Formula :

$\star\small{\underline{ \boxed{\sf{\red{S.I = \dfrac{P \times R \times T}{100}}}}}}$

• S.I = Simple Interest
• P = Principle
• R = Rate
• T = Time

Solution :

Substituting all the given values in the formula to find the Simple Interest :

${\dashrightarrow{\small{\sf{S.I = \dfrac{P \times R \times T}{100}}}}}$

${\dashrightarrow{\small{\sf{2000= \dfrac{P \times 5 \times 1}{100}}}}}$

${\dashrightarrow{\small{\sf{2000= \dfrac{P \times 5}{100}}}}}$

${\dashrightarrow{\small{\sf{2000= \dfrac{5P}{100}}}}}$

${\dashrightarrow{\small{\sf{P = 2000 \times \dfrac{100}{5}}}}}$

${\dashrightarrow{\small{\sf{P = 2000 \times \cancel{\dfrac{100}{5}}}}}}$

${\dashrightarrow{\small{\sf{P = 2000 \times 20}}}}$

${\dashrightarrow{\small{\sf{P =Rs.40000}}}}$

$\star\small{\underline{ \boxed{\sf{\red{P = Rs.40000}}}}}$

Hence, the sum Bharat borrowed is Rs.40000.

$\rule{190}1$