Answer:
Distance (d) = 15
Step-by-step explanation:
The given requires the distance between the point of origin, (0, 0), and (-12, 9). We can use the following distance formula for this problem:
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(x_2-x_1)^2\:+\:(y_2-y_1)^2}}[/tex]
Let (x₁, y₁) = (0, 0)
(x₂, y₂) = (-12, 9)
Substitute these values into the distance formula.
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(x_2-x_1)^2\:+\:(y_2-y_1)^2}}[/tex]
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(-12\:-\:0)^2\:+\:(9-0)^2}}[/tex]
Perform the required subtraction within each parenthesis:
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{(-12)^2\:+\:(9)^2}}[/tex]
Next, take the squared values of -12 and 9 under the radical:
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{144\:+\:81}}[/tex]
Add 144 and 81:
[tex]\displaystyle\mathsf{Distance(d)=\:\sqrt{225}}[/tex]
Distance (d) = 15
Therefore, the distance between the point of origin and (-12, 9) is 15.