nfarraj
nfarraj nfarraj
  • 26-12-2021
  • Mathematics
contestada

need help with this problem

need help with this problem class=

Respuesta :

mahanadeem2002
mahanadeem2002 mahanadeem2002
  • 26-12-2021

Answer:

x = 6

Step-by-step explanation:

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Аноним Аноним
  • 26-12-2021

Answer:

Step-by-step explanation:

tan30 = x/12

x = 12tan30

x = 12(sin30/cos30)

x = 12(½ / ½√3)

x = 12/√3

x = (12/3)√3

x = 4√3

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