Question

Suppose $\frac{1}{2} + \frac{1}{3} + \ldots +\frac{1}{x} > 1\frac{1}{2}$. What is the smallest possible value for $x$?

Answer 1

The smallest possible value of x is the value less than 2/3

Given the series $\frac{1}{2} + \frac{1}{3} + \ldots +\frac{1}{x} > 1\frac{1}{2}$

We need to find the smallest possible value of x as shown:

$\frac{1}{x} > 1\frac{1}{2}\\ \frac{1}{x} > \frac{3}{2}$

Reciprocate both sides

$x < \frac{2}{3}$

Hence the smallest possible value of x is the value less than 2/3

Learn more on inequality here: https://brainly.com/question/4192645

Answer 2

Answer:x=7

Step-by-step explanation: