Question

$\huge \dag \sf{Answer \: it}$​
$solve \: for \: x \\ \\ {2}^{ {x}^{2} } 2 \frac{3x \sqrt{3} }{2} = 8$
Don't spam and Don't copy.
Need answer with explanation
Don't answer if you don't know

Best of luck guys
​

Answer 1

Answer:

Answer: x = √3 and 8/(3√3)

Step-by-step explanation:

${ \rm{({2}^{ {x}^{2} } )(2 \frac{3x \sqrt{3} }{2}) = 8}}$

• For the first bracket:

${ \rm{ {2}^{ {x}^{2} } = 8}} \\ \\ { \rm{ {2}^{ {x}^{2} } = {2}^{3} }} \\ \\ { \rm{ {x}^{2} = 3}} \\ \\ { \rm{x = \pm \sqrt{3} }}$

• For the second bracket;

${ \rm{ 2 \frac{3x \sqrt{3} }{2} = 8}} \\ \\ { \rm{3x \sqrt{3} = 8 }} \\ \\ { \rm{3x = \frac{8}{ \sqrt{3} } }} \\ \\ { \rm{x = \frac{8}{3 \sqrt{3} } }}$