Respuesta :

Answer:

[tex]\displaystyle [9, 4\frac{1}{2}][/tex]

Step-by-step explanation:

I figure these exercises out by numeric association. I see a 3, so I know right away that there might be a 9 somewhere. So, you start by plugging 3 in for [tex]\displaystyle x,[/tex] THEN plug [tex]\displaystyle 1\frac{1}{2}[/tex] in for [tex]\displaystyle y[/tex] sinse there are twise the quantity of [tex]\displaystyle y[/tex] than there are of [tex]\displaystyle x.[/tex] Now, doing so will give you [tex]\displaystyle 24 ≠ 18.[/tex] This tells you to try another pattern, so go with plugging [tex]\displaystyle 4\frac{1}{2}[/tex] in for [tex]\displaystyle y[/tex] and [tex]\displaystyle 9[/tex] in for [tex]\displaystyle x[/tex]. Doing so gives you what you are looking -- [tex]\displaystyle 36 = 36.[/tex] Therefore, the association wourked perfectly. ☑

I am joyous to assist you at any time.

That locked sign defines that both sides are equal.

The equations are

  • 2x=4y=>x=2y--(1)
  • 3x+9=2x+4y=>x+9=4y=>x=4y-9--(2)

From (1) and (2)

[tex]\\ \rm\Rrightarrow 4y-9=2y[/tex]

[tex]\\ \rm\Rrightarrow 2y=9[/tex]

[tex]\\ \rm\Rrightarrow y=9/2=4.5[/tex]

Put in eq(1)

  • x=2(4.5)=9

Hence

  • (x,y)=(9,4.5)
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