Question

find all complex solutions of 3x^2-6x+1=0

Answer 1

Answer:

$x=\frac{3+\sqrt{6} }{3}, \frac{3-\sqrt{6} }{3}$

Step-by-step explanation:

Answer 2

Let's see

$\\ \rm\rightarrowtail 3x^2-6x+1=0$

$\\ \rm\rightarrowtail x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\\ \rm\rightarrowtail x=\dfrac{6\pm \sqrt{36-12}}{6}$

$\\ \rm\rightarrowtail x=\dfrac{6\pm \sqrt{24}}{6}$

$\\ \rm\rightarrowtail x=\dfrac{6\pm 2\sqrt{3}}{6}$

$\\ \rm\rightarrowtail x=\dfrac{3+\sqrt{3}}{6}$