Question

Jason stands in the corner of a very large field. He walks, on a bearing of 030°,
a distance of d metres. Jason then changes direction and walks twice as far on a new
bearing of 120°. At the end of the walk Jason calculates both the distance he must
walk and the bearing required to return to his original position. Given that the total
distance walked is 120 metres, what answers will Jason get if he is correct?

Answer 1

Answer:

Step-by-step explanation:

d + 2d = 120

3d = 120

d = 40 m

east distance was 40cos30 + 80cos120 = -5.35898 m

north distance was 40sin30 + 80sin120 = 89.282032

as 30° and 120° bearings are 90° apart, Jason needs to walk

D = √(d² + (2d)²) = d√5 or 40√5 meters or about 89.44 m to return to his original position.

we could also use √(-5.35898² + 89.282032²) = 89.44 m

direction will be

θ = arctan -89.28/5.359 = -86.565° or a bearing of 273.4°