Question

A small car of mass 1200 kg traveling east at 60m/s collides at an intersection with a truck of mass 3000 kg that is traveling due north at 40 m/s. The two vehicles are locked together. What is the velocity of the combined wreckage

Answer 1

Answer:

11.4m/s I think mb not 100% lol

Explanation:

P=mv

P1 = 1200×60 = 72000

P2 = 3000×40 = 120000

120000+(-72000) = 48000

v=P÷m

m=1200+3000 = 4200

48000÷4200 = 11.4m/s

Answer 2

v2f= 2⋅m1 (m2+m1) v1i + (m2−m1)(m2+m1) v2i v 2

meaning that

2 x 1200 ( 3000 + 1200) 60 + (3000-1200)(3000+1200) 40f =

2400 (4200) 60 + (1800) (4200) 40f =

10080000 (60) +  75600000 (40)

604800000 + 3024000000

3628800000? this is what i got

f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i