Question

What is the maximum speed with which a 1200-kgkg car can round a turn of radius 93.0 mm on a flat road if the coefficient of static friction between tires and road is 0.45

Answer 1

Answer:

Explanation:

Radius of 93 mm seems really small, but OK...

The maximum friction force will equal the maximum centripetal force

mv²/R = μmg

     v² = μgR

      v = √(0.45(9.8)(0.093)) = 0.64 m/s

IF you really meant to say 93.0 m,

THEN

v = √(0.45(9.8)(93)) = 20.25... = 20 m/s