[tex]\huge \bf •Answer •\\ [/tex]
1188 g
[tex]\huge \bf •Solution •\\ [/tex]
We know,
[tex]\sf \dfrac{mass \: \: of \: \: solute}{mass \: \: of \: \: solution} \times 100= concentration \: \: of \: \: solution \\ = > \sf \dfrac{mass \: \: of \: \: solute}{mass \: \: of \: \: solute + mass \: \: of \: \: solvent} \times 100= concentration \: \: of \: \: solution[/tex]
Given, concentration of solution = 1%
Mass of sugar (solute) = 12 g
Let the mass of water (solvent) be x.
Therefore,
[tex]\sf \dfrac{12g}{12g + x} \times 100= 1 \\ \sf = > 1200g= 12g + x \\ \sf= > (1200 - 12)g = x \\ \sf = > x = 1188g[/tex]
Hope you could get an idea from here.
Doubt clarification - use comment section.
