Question

A spring in a dart gun is compresscht a distance of 0.05 m. The spring has a spring constant
of 1,115 N/m. If the dart has a mass of 0.025 kg, determine the velocity of the dart as it
leaves the dart gun.

Answer 1

Answer:

Explanation:

ASSUMING that the dart is fired horizontally so that gravity potential energy considerations are not needed. Also ignoring friction work.

The spring potential will convert to kinetic.

KE = PS

½mv² = ½kx²

     v = $\sqrt{kx^2/m}$

     v = $\sqrt{1115(0.05^2)/0.025}$

     v = 10.55935...

     v = 11 m/s