ANSWER FOR BRAINIEST!!!
How do you answer this and what did I do incorrectly?
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Answer:
x=5[tex]\frac{16}{3}[/tex]/(4-[tex]\frac{16}{3}[/tex])
Step-by-step explanation:
Hi, these are not my strong point, Sorry if its incorrect.
6-[tex]\frac{2}{3}[/tex](x+5)=4x
I first did 6-[tex]\frac{2}{3}[/tex]
6/1 -2/3, 18/3-2/3 =16/3
[tex]\frac{16}{3}[/tex](x+5)=4x
I then expanded the bracket to get [tex]\frac{16}{3}[/tex]x+5[tex]\frac{16}{3}[/tex]
[tex]\frac{16}{3}[/tex]x+5[tex]\frac{16}{3}[/tex]=4x
Then I took away [tex]\frac{16}{3}[/tex]x from both sides to get.
5[tex]\frac{16}{3}[/tex]=4x-[tex]\frac{16}{3}[/tex]x
I then factorised x out
5[tex]\frac{16}{3}[/tex]=x(4-[tex]\frac{16}{3}[/tex])
I then divided by the bracket to get:
x=5[tex]\frac{16}{3}[/tex]/(4-[tex]\frac{16}{3}[/tex])
Answer:
4/7
Step-by-step explanation:
[tex]6 - \frac{2}{3} (x + 5) = 4x[/tex]
U take -2/3 into the brackets
[tex]6 - \frac{2}{3} x - \frac{10}{3} = 4x[/tex]
Put all values with x on one side
[tex]6 - \frac{10}{3} = 4x + \frac{2}{3} x[/tex]
Ensure that they all have the same denominator so that u can add and subtract
[tex] \frac{18}{3} - \frac{10}{3} = \frac{12}{3} x + \frac{2}{3} x[/tex]
[tex] \frac{8}{3} = \frac{14}{3} x[/tex]
Drop the denominator since they both have the same denominator
[tex]8 = 14x[/tex]
divide both sides by 14
[tex] \frac{8}{14} = \frac{14}{14} x[/tex]
[tex]x = \frac{4}{7} [/tex]