Answer:
Step-by-step explanation:
Parallel lines have the same slope. The reference line is this case is 3x-y=5. Let's rearrange it into slope/intercept for of y = mx + b, where m is the slope and b is the y-intercept.
3x-y=5
-y=5 -3x
y=3x - 5
We see that the slope is 53. Our parallel line will have the same slope:
y = 3x + b
We need to find a value for b that forces the line through point (2,7). We can do that by entering the point into the equation and solving for b.
y = 3x + b
7 = 3*(2) + b for (2,7)
7 = 6 + b
b = 1
The line becomes y = 3x + 1
See attachment.
