Given AB/CD = AO/OC = BO/OD Prove: <1 is congruent to < 2

The common ratio of the corresponding sides of the given triangles
indicate that the triangles are similar.
Reasons:
The given relationship are;
The ratio of each side of ΔAOB to the corresponding side of ΔCOD is constant, therefore;
ΔAOB is similar to ΔCOD by Side-Side-Side similarity postulate
Which gives;
ΔAOB ~ ΔCOD
Therefore, the three angles of ΔAOB are congruent to their corresponding angles of ΔCOD, which gives;
(CASTC); Corresponding Angles of Similar Triangles are Congruent
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