Question

22. A skater glides off a frozen pond onto a patch of ground at a speed of 1.8 m/s. Here she is slowed at a
constant rate of 3.00 m/s2. How fast is the skater moving when she has slid 0.37 m across the ground?

Answer 1

Answer:

the answer would be 1.01 m/s

Explaination:

v^2 = u^2 + 2as

(substitute u,a,s)

v^2 = 1.8 + 2 * -3 * 0.37

v^2 = 3.24 - 2.22

v^2 = 1.02

(take the square roots)

v = $\sqrt{1.02}$

v = 1.00995049384

v = 1.01 m/s