[tex]\dfrac 7{12} + \dfrac 56\\\\\\=\dfrac 7{12} + \dfrac{10}{12}\\\\\\=\dfrac{7+10}{12}\\\\\\=\dfrac{17}{12}[/tex]
what does [tex] \frac{7}{12} + \frac{5}{6} [/tex] equal
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LCM of 12 and 6 = 12