Question

A driver starts his parked car and within 6.0 seconds, reaches a velocity of 54.0 km/h. What is his acceleration, in m/s2?

Answer 1

Answer:

Explanation:

a = Δv/t

54.0 km/h(1000 m/km / 3600 s/hr) = 15.0 m/s

a = (15.0 - 0.00) / 6.0

a = 2.5 m/s²