Question

Exactly seven years ago, Sam was 5 times the age of Janet. Exactly two years ago, Sam was 3 times the age of Janet. What is the sum of their ages today? Your answer

Answer 1

Answer:

Its 64

Explanation:

Lets start with the equation;

x-7=J-5x5

x-2=J-2x3

Solve for x and J, then you'll get 64.