Answer:
Explanation:
The time of flight must be identical for both vertical and horizontal components. call it "t"
to fall 10 m from rest would take
s = ½at²
t = √(2s/g)
t = √(2(10) / 9.8)
t = 1.428571...s
So the initial vertical velocity must be
v₀ = gt
v₀ = 9.8(1.428571)
v₀ = 14 m/s
we can now determine the throwing angle
sinθ = 14/21
θ = 41.810314,,,
θ = 41.81°
The horizontal distance is the horizontal velocity times the time of flight
Δx = (21cos41.81)(1.428571)
Δx = 22.360673...
Δx = 22.36 m
