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samueladesida43

The mass of SO2 needed to produce 530 g of SO3 is 4241.2grams.

  • The balanced chemical reaction between sulphur IV oxide and oxygen to produce sulphur VI oxide is as follows:

  • 2SO2 + O2 → 2SO3

  • According to this equation, 2 moles of SO2 will react to produce 2 moles of SO3.

  • First, we convert 530g of SO3 to moles as follows:

  • Molar mass of SO3 = 80.06 g/mol

  • no. of moles of SO3 = 530g ÷ 80.06g/mol = 6.62moles

  1. Since 2 moles of SO2 will react to produce 2 moles of SO3.
  2. 6.62 moles of SO3 will be produced by 6.62 moles of SO2.

  • Next, we convert 6.62 moles of SO2 to mass as follows:

  • mass of SO2 = 6.62moles × 64.066g/mol

  • mass of SO2 = 424.12g

  • Therefore, the mass of SO2 needed to produce 530 g of SO3 is 4241.2grams.

Learn more about how to calculate stoichiometric mass as follows: https://brainly.com/question/9743981?referrer=searchResults

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