Answer:
let
s = the number of stools bought, s is integer
c = the number of chairs bought, c is integer
they need to buy 25 more chairs than stools
c = s + 25 => s = c - 25
the chairs cost $32 each and the stools cast $28 each and the budget is $2,620
32c + 28s <= 2620
if i plug s = c - 25 in the above inequality i get
32c + 28(c - 25) <= 2620
by solving the inequality we find
c <= 55.33
since c is integer we can write c<=55
they can buy 55 chairs the most.