Question

A rock tied to the end of a string moves in a circle at a constant speed of 2.5 m/s and experiences an acceleration of 4.0 m/s. What is the radius of the
circle of its motion?
O 1.60 m

Answer 1

The radius of the circular motion at the given speed is 1.56 m.

The given parameters;

• speed of the rock, v = 2.5 m/s
• acceleration of the rock, a = 4 m/s²

The radius of the circular motion is calculated by using centripetal acceleration formula as follows;

$a_c = \frac{v^2}{r} \\\\r = \frac{v^2}{a_c} \\\\r = \frac{2.5^2}{4} \\\\r = 1.56 \ m$

Thus, the radius of the circular motion at the given speed is 1.56 m.

Learn more about centripetal acceleration here: https://brainly.com/question/79801