Three-fourths of the fudge at the fudge shop on Monday morning contain nuts. Helena works at the fudge shop and prepares 12 3/4 pounds of fudge containing walnuts to fulfill a special order Monday afternoon. With this additional amount of fudge, there are at least 29 5/8 pounds of fudge containing nuts at the fudge shop on Monday (a) Write an inequality that represents the scenario. Begin by defining your variable. (b) Solve the inequality. Show your work. (c) Fudge is packaged into 1-pound boxes. What is the fewest number of boxes of fudge at the fudge shop Monday morning?​

Respuesta :

At least means less than or equal to.

Fewest means the smallest number of boxes.

12 3/4 +x ≥ 29 5/8

x ≥  16 7/8

The fewest number of boxes would be almost ≅ 42 boxes

Part A:

Let x denote the amount of fudge at the shop.

Helena prepares 12 3/4 pounds of fudge containing nuts.

Mathematically, the total amount of fudge on Monday will be

12 3/4 +x

Of this amount of fudge  there are at least 29 5/8 pounds of fudge containing nuts at the fudge shop on Monday

12 3/4 +x ≥ 29 5/8

Part B:

The inequality can be solved

12 3/4 +x ≥ 29 5/8

x ≥ 29 5/8- 12 3/4

x ≥  29- 12     5/8- 3/4    The whole numbers are subtracted and the fractions are solved separately to avoid long calculations.

x ≥  17  (5-6)/8

x ≥  17 - 1/8

x ≥  (136-1)/8

x ≥  (135)/8

x ≥  16 7/8

Part C :

To  find the number of boxes we divide the equal number of pounds .

12 3/4 + 29 5/8

12 + 29   3/4 + 5/8

41  11/8

42 3/8

The fewest number of boxes would be almost ≅ 42 boxes

At least problem can be understood by the following link.

https://brainly.com/question/24863377