Question

In an experiment, you were required to calculate the percent yield of the compound. If the beaker weighed 10.20 g and the beaker dried substance weighed 16.54 g, what is the percent yield of the product if you expected to obtain 7.62g of produce

Answer 1

The percent yield of the product is 83.20% if the beaker weighs 10.20 g, the dry substance in the beaker weighs 16.54 g, and the expected mass is 7.62 g.  

The percent yield of the product is given by:

$\% = \frac{m_{e}}{m_{t}} \times 100$

Where:

$m_{e}$: is the experimental mass

$m_{t}$: is the theoretical mass = 7.62 g

We can obtain the experimental mass by substrating the mass of the beaker from the mass of the dry substance in the beaker.

$m_{e} = (16.54 - 10.20) g = 6.34 g$

Hence, the percent yield is:

$\% = \frac{6.34}{7.62} \times 100 = 83.20 \%$

Therefore, the percent yield of the product is 83.20%.

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I hope it helps you!