The number of ions in 0.20 mole of (NH₄)₃PO₄ is 1.204×10²³ ions
From Avogadro's hypothesis,
1 mole of (NH₄)₃PO₄ = 6.02×10²³ ions
- With the above information in mind, we can determine the number of ions in 0.20 mole of (NH₄)₃PO₄ as illustrated below:
1 mole of (NH₄)₃PO₄ = 6.02×10²³ ions
Therefore,
0.20 mole of (NH₄)₃PO₄ = 0.2 × 6.02×10²³
0.20 mole of (NH₄)₃PO₄ = 1.204×10²³ ions
Thus, 1.204×10²³ ions are present in 0.20 mole of (NH₄)₃PO₄
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